document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180199>Question 1180199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Sizwe drives from A to B and takes 60 minutes. Thabo drives from B to A and takes 90<BR>\n" );
document.write( "minutes. They both start at 10:00 and drive at constant speeds. At what time do they pass<BR>\n" );
document.write( "each other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809809 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809809\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> each minute, S goes (1/60) of the way and T goes 1/90 of the way.<BR>\n" );
document.write( "How long does it take for their sum to be 1?<BR>\n" );
document.write( "(x/60)+(x/90) =1, where x is the number of minutes.<BR>\n" );
document.write( "multiply by 180 both sides<BR>\n" );
document.write( "3x+2x=180=5x<BR>\n" );
document.write( "x=36 minutes<BR>\n" );
document.write( "so S has gone 60% of the way and T has gone 40% of the way. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );