document.write( "Question 1180195: Suppose that a brand of lightbulb lasts on average 2243 hours with a standard deviation of 199 hours. Assume the life of the lightbulb is normally distributed. Calculate the probability that a particular bulb will last from 1797 to 2406 hours?\r
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document.write( "P(1797 < X < 2406) = \r
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document.write( "Enter your answer as a number accurate to 4 decimal places.\r
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document.write( "*Note: all z-scores must be rounded to the nearest hundredth. \n" );
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Algebra.Com's Answer #809805 by Boreal(15235) You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "z lower=(1797-2243)/199=-2.24 \n" ); document.write( "z upper=163/199=0.82 \n" ); document.write( "the probability is 0.7813 \n" ); document.write( "- \n" ); document.write( "check on calculator with 2 VARS 2 normalcdf (1797,2406,2243,199)ENTER=0.7811, which is slightly more accurate, since the z-values are not rounded until the calculation. This is obtained with 3 decimal places for z. \n" ); document.write( " \n" ); document.write( " |