document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180187>Question 1180187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the arithmetic serie whose first two terms are -12 and -8, respectively, and whose last term is 124. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809794 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the sum of the arithmetic serie whose first two terms are -12 and -8, respectively, and whose last term is 124.\r<BR>\n" );
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document.write( "-12, -8, ...........124\r<BR>\n" );
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document.write( "a= -12, d=4, tn =124\r<BR>\n" );
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document.write( "tn = nth term = a+(n-1)d\r<BR>\n" );
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document.write( "124 = -12+(n-1)4\r<BR>\n" );
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document.write( "136 = 4n-4<BR>\n" );
document.write( "140 = 4n<BR>\n" );
document.write( "n= 35 There area 35 terms\r<BR>\n" );
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document.write( "Sum of terms Sn = (n/2) * (a+l) where a is the first term and l is the last term\r<BR>\n" );
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document.write( "Sn = (35/2) (-12+124)\r<BR>\n" );
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document.write( "= 35*112/2\r<BR>\n" );
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document.write( "35* 56 =1960\r<BR>\n" );
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document.write( "sum of the arithmetic series = 1960 </SPAN>\n" );
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