document.write( "Question 110992: 1.) 3x/(x+1) + 6/2x = 7/x\r
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document.write( "2.) 6x/(x+4) + 4 = 2x+2/(x-1)\r
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document.write( "3.) 7x+1/2x+5 + 1 =10x-3/3x\r
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document.write( "4.) 10/x^2-2x + 4/x = 5/x-2
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Algebra.Com's Answer #80976 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1.) 3x/(x+1) + 6/2x = 7/x \n" ); document.write( "x(x+1) is the LCM \n" ); document.write( "Multiply thru by the LCM: \n" ); document.write( "3x^2 + 3(x+1) = 7(x+1) \n" ); document.write( "3x^2 + 3x+3 = 7x+7 \n" ); document.write( "3x^2-4x-3=0 \n" ); document.write( "x = [4 +- sqrt(16-4*3*-3)]/6 \n" ); document.write( "x = [4 +- sqrt(52)]/6 \n" ); document.write( "x = [4 +- 2sqrt(13)]/6 \n" ); document.write( "x = [2 +- sqrt(13)]/3 \n" ); document.write( "x = (2 + sqrt(13))/3 or x = (2 - sqrt(13))/3 \n" ); document.write( "==========================\r \n" ); document.write( "\n" ); document.write( "2.) 6x/(x+4) + 4 = (2x+2)/(x-1) \n" ); document.write( "Multiply thru by (x+4)(x-1) to get: \n" ); document.write( "6x(x-1) + 4(x+4)(x-1) = 2(x+1)(x+4) \n" ); document.write( "6x^2-6x + 4x^2+12x-16 = 2x^2+10x+8 \n" ); document.write( "8x^2 -4x -24 = 0 \n" ); document.write( "4(2x^2 -x -12) = 0 \n" ); document.write( "2x^2 - x -12 = 0 \n" ); document.write( "x = [1 +- sqrt(1 -4*2*-12)]/4 \n" ); document.write( "x = [1 +- sqrt(97)]/4 \n" ); document.write( "x = (1+ sqrt(97))/4 or x = (1-sqrt(97))/4 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "3.) 7x+1/2x+5 + 1 =10x-3/3x \n" ); document.write( "4.) 10/x^2-2x + 4/x = 5/x-2\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |