document.write( "Question 1180156: I am thinking of two numbers. Twice the first number added to four times the second number is 22. The first number is one less than twice the second number. Find the two numbers.
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #809758 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
I am thinking of two numbers.
\n" ); document.write( " a & b
\n" ); document.write( "Twice the first number added to four times the second number is 22.
\n" ); document.write( " 2a + 4b = 22
\n" ); document.write( "simplify, divide by2
\n" ); document.write( " a + 2b = 11
\n" ); document.write( "The first number is one less than twice the second number.
\n" ); document.write( " a = 2b - 1
\n" ); document.write( "write as
\n" ); document.write( " a - 2b = -1
\n" ); document.write( "Find the two numbers.
\n" ); document.write( "using elimination
\n" ); document.write( " a + 2b = 11
\n" ); document.write( " a - 2b = -1
\n" ); document.write( "-------------------addition eliminates b, find a
\n" ); document.write( " 2a = 10
\n" ); document.write( " a = 10/2
\n" ); document.write( " a = 5
\n" ); document.write( "find b using the simplified equation
\n" ); document.write( " 5 + 2b = 11
\n" ); document.write( " 2b = 11 - 5
\n" ); document.write( " 2b = 6
\n" ); document.write( " b = 6/2
\n" ); document.write( " b = 3
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check in the 2nd original equation
\n" ); document.write( "5 - 2(3) = -1\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );