document.write( "Question 1180051: If log3(x − 3) − log 1/3(x + 1) is expressed in terms of a logarithm with base 9 .How is going to be ? \n" ); document.write( "
Algebra.Com's Answer #809753 by greenestamps(13206)\"\" \"About 
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\n" ); document.write( "Your notation is indeed unclear....

\n" ); document.write( "For the problem to make sense, I believe the given expression is this:

\n" ); document.write( "\"log%283%2C%28x-3%29%29-log%281%2F3%2C%28x%2B1%29%29\"

\n" ); document.write( "To write this expression using base 9 logs, note

\n" ); document.write( "\"9+=+3%5E2\"
\n" ); document.write( "and
\n" ); document.write( "\"9+=+%281%2F3%29%5E%28-2%29\"

\n" ); document.write( "Then

\n" ); document.write( "\"log%283%2C%28x-3%29%29=2log%289%2C%28x-3%29%29\"
\n" ); document.write( "\"log%281%2F3%2C%28x%2B1%29%29=-2log%289%2C%28x%2B1%29%29\"

\n" ); document.write( "Then

\n" ); document.write( "

\n" ); document.write( "The expression can then be written in various forms:

\n" ); document.write( "\"2log%289%2C%28%28x-3%29%28x%2B1%29%29%29\"

\n" ); document.write( "\"log%289%2C%28%28x-3%29%28x%2B1%29%29%5E2%29\"

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