document.write( "Question 110995: Please help me with this problem.Solve: x^2-3x-40=0 \n" ); document.write( "
Algebra.Com's Answer #80974 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x-40=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-8%29%28x%2B5%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x-8=0\" or \"x%2B5=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=8\" or \"x=-5\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "So our solutions are \"x=8\" or \"x=-5\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph \"y=x%5E2-3x-40\" we get\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C+x%5E2-3x-40%29+\"\r
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\n" ); document.write( "\n" ); document.write( "and we can see that the graph has roots at \"x=8\" and \"x=-5\", so this verifies our answer.\r
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