document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179902>Question 1179902</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you draw one card from a standard deck of cards, what is the probability of drawing <BR>\n" );
document.write( "a. a 10 or a diamond<BR>\n" );
document.write( "b. a face card or an ace<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809711 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809711\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> there are 4 10s and 13 diamonds.  That is 17 cards, but the 10 of diamonds is counted twice, so the number of possibilities is 16 with 52 cards. That probability is 16/52 or 4/13.<BR>\n" );
document.write( "-<BR>\n" );
document.write( "probability of a face card is 12/52, 3 face cards from each of 4 suits. There are four aces, and the sum of those numerators is 16, so the probability is 16/52 or 4/13. There is no duplication since both groups are mutually exclusive. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );