document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180083>Question 1180083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are possible number of positive ,negative and imaginary zeros of P(x) .\r<BR>\n" );
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document.write( "P(x)= 2x^5 + x^3 - 2x^2 + 3x -5   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809702 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Use Descartes' rule of signs.<br><BR>\n" );
document.write( "In P(x), there are 3 sign changes; the possible numbers of positive real roots are 3 or 1.<br><BR>\n" );
document.write( "In P(-x), there are 0 sign changes; the number of negative real roots is 0.<br><BR>\n" );
document.write( "ANSWER: There are two possibilities:<BR>\n" );
document.write( "(a) 3 positive real roots and one pair of imaginary roots; or<BR>\n" );
document.write( "(b) 1 positive real root and two pairs of imaginary roots<br><BR>\n" );
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