document.write( "Question 1180107: The generation time G for a particular bacterium is the time it takes for the population to double. The bacteria increase in population is shown by the formula G = t over 3.3log a p, where t is the time period of the population increase, a is the number of bacteria at the beginning of the time period, and P is the number of bacteria at the end of the time period. If the generation time for the bacteria is 6 hours, how long will it take 8 of these bacteria to multiply into a colony of 7681 bacteria?\r
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Algebra.Com's Answer #809696 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "This problem is constructed by its composer according the following principle\r
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document.write( "    Push all known words and formulas into one box.\r\n" );
document.write( "    Do not care about the meaning.\r\n" );
document.write( "    and let the reader spends his (or her) time,\r\n" );
document.write( "    while we will laugh on him.\r\n" );
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\n" ); document.write( "\n" ); document.write( "I know the method on how to solve it.\r
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\n" ); document.write( "\n" ); document.write( "This method is  FILTERING  OUT  ALL  UNNECESSARY  WORDS.\r
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\n" ); document.write( "\n" ); document.write( "Following this method,  I read the problem in this way\r
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\n" ); document.write( "\n" ); document.write( "    1)   We are given the initial number of bacteria  (8)\r
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\n" ); document.write( "\n" ); document.write( "    2)   We are given the doubling time  (6  hours)\r
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\n" ); document.write( "\n" ); document.write( "    3)  We are asked about the time getting  N = 7681 bacteria.\r
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\n" ); document.write( "\n" ); document.write( "    It is the standard problem on exponential growth.\r
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document.write( "    N(t) = 8*2^(t/6)\r\n" );
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document.write( "    7681 = 8^2^(t/6)\r\n" );
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document.write( "    \"7681%2F8\" = 2^(t/6)\r\n" );
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document.write( "    960.125 = 2^(t/6)\r\n" );
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document.write( "    \"log%282%2C%28960.125%29%29\" = \"t%2F6\"     logarithm base 2\r\n" );
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document.write( "    t = \"6%2Alog%282%2C%28960.125%29%29\" = 59.44 hours.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "The rest of the non-necessary words in the post is  GARBAGE.\r
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\n" ); document.write( "\n" ); document.write( "In simple terms,  posting such  \"problems\"  is mocking tutors.\r
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\n" ); document.write( "\n" ); document.write( "Next time I will not allow for such gibberish to come to the forum:\r
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\n" ); document.write( "\n" ); document.write( "        as soon as I will see it,  I will delete it  (without explanations).\r
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