document.write( "Question 110890: a cargo plane flew to the maintenance facility and back it took one hour less time to get there than it did to get back. the average speed on the trip there was 220mph the average speed on the way back was 200mph how many hours did the trip take \n" ); document.write( "
Algebra.Com's Answer #80968 by ankor@dixie-net.com(22740)\"\" \"About 
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A cargo plane flew to the maintenance facility and back it took one hour less time to get there than it did to get back. the average speed on the trip there was 220 mph the average speed on the way back was 200 mph how many hours did the trip take
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\n" ); document.write( "Find the times of each portion of the trip
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\n" ); document.write( "Let t = time for the 220 mph portion:
\n" ); document.write( "Then
\n" ); document.write( "(t+1) = time for the 200 mph portion
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\n" ); document.write( "The dist to and the dist from are equal, so write a dist equation;
\n" ); document.write( "Dist = speed * time
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\n" ); document.write( "Dist to = dist back
\n" ); document.write( "220t = 200(t+1)
\n" ); document.write( "220t = 200t + 200
\n" ); document.write( "220t - 200 = 200
\n" ); document.write( "20t = 200
\n" ); document.write( "t = 200/20
\n" ); document.write( "t = 10 hrs to
\n" ); document.write( "Then
\n" ); document.write( "10 + 1 = 11 hrs back
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\n" ); document.write( "Total hrs: 10 + 11 = 21 hrs for the round trip
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\n" ); document.write( "Check solutions by ensuring that the distances are equal:
\n" ); document.write( "10(220) = 2200 mi
\n" ); document.write( "11(200) = 2200 mi\r
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