document.write( "Question 1180049: How many ways can 11 people be seated around a circular table if two of them insist to sit next to each other? \r
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Algebra.Com's Answer #809643 by ikleyn(52781) $\"\"$ $\"About$

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document.write( "Then we consider this special pair as one (glued) object, and we, actually, \r\n" );
document.write( "have 10 objects then (instead of 11) to arrange around the circular table.\r\n" );
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document.write( "We can arrange 10 objects around the circular table by 9! ways,\r\n" );
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document.write( "but this special object can be in one of the two states (AB) or (BA).\r\n" );
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document.write( "Therefore, the total number of all possible arrangements (circular permutations) of this kind is\r\n" );
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document.write( "    2*9! = 2 * (9*8*7*6*5*4*3*2*1) =  725760.     ANSWER\r\n" );
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