document.write( "Question 1180034: A furniture shop refinishes cabinets. Employees use one of two methods to refinish each cabinet. Method I takes 1.5 hours and the material costs $10. Method II takes 2 hours, and the material costs $9. Next week, they plan to spend 288 hours in labor and $1530 in material for refinishing cabinets. How many cabinets should they plan to refinish with each method? \n" ); document.write( "
Algebra.Com's Answer #809622 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x Method I tables \n" ); document.write( " y Method II tables \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "1.50 x + 2.00 y = 288.00 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "10.00 x + 9.00 y = 1530.00 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -9.00 \n" ); document.write( "Multiply (2) by 2.00 \n" ); document.write( "-13.50 x -18.00 y = -2592.00 \n" ); document.write( "20.00 x 18.00 y = 3060.00 \n" ); document.write( "Add the two equations \n" ); document.write( "6.50 x = 468.00 \n" ); document.write( "/ 6.50 \n" ); document.write( "x = 72.00 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1.50 x + 2.00 y = 288.00 \n" ); document.write( "108.00 + 2.00 y = 288.00 \n" ); document.write( " 2.00 y = 180.00 \n" ); document.write( " y = 90.00 \n" ); document.write( "Ans x = 72.00 \n" ); document.write( " y = 90.00 \n" ); document.write( " 72.00 Method I tables \n" ); document.write( " 90.00 Method II tables \n" ); document.write( " \n" ); document.write( " |