document.write( "Question 1180038: Towns A and B are 300 km apart. Samuel travels from A to B at a speed of 80 km/h. Darius leaves
\n" ); document.write( "30 minutes after Samuel and also travels from A to B, at a speed of 100 km/h. Darius overtakes Samuel
\n" ); document.write( "t hours after Samuel has left town A .How long will it be before Darius overtakes Samuel? \n" ); document.write( "
Algebra.Com's Answer #809621 by mananth(16946)\"\" \"About 
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Towns A and B are 300 km apart. Samuel travels from A to B at a speed of 80 km/h. \r
\n" ); document.write( "\n" ); document.write( "Darius leaves 30 minutes after Samuel and also travels from A to B, at a speed of 100 km/h. Darius overtakes Samuel\r
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\n" ); document.write( "\n" ); document.write( "When Dairus leaves Samuel is 40 km ahead of Darius. (After 1/2 hour)\r
\n" ); document.write( "\n" ); document.write( "The catchup distance is 40 km/h\r
\n" ); document.write( "\n" ); document.write( "Catch up speed is 100-80 = 20 km/h\r
\n" ); document.write( "\n" ); document.write( "Catch up time = catch up distance/ catch up speed\r
\n" ); document.write( "\n" ); document.write( "=40/20 = 2hours\r
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