document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180023>Question 1180023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bubba was boating down the river. He realize that in half the time it took him to go 84 miles downstream, he could go 18 miles upstream. If the boat could travel 15 mph in still water, how fast was the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809607 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39625)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <PRE STYLE=\"white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;\">\r\n" );
document.write( "            SPEED      TIME                 DIST.\r\n" );
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document.write( "DOWN         15+c      84/(c+15)              84\r\n" );
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document.write( "UP           15-c      18/(15-c)              18\r\n" );
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