document.write( "Question 1179955: Find the equation of the line tangent to the circle at the indicated point.
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document.write( "x^2+y^2-6x+8y-144 = 0 at point (8,8) \n" );
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Algebra.Com's Answer #809538 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "centre is ( \n" ); document.write( "\n" ); document.write( "slope of line through ( \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since tangent is perpendicular to it, the slope of line of the tangent is therefore \n" ); document.write( "\n" ); document.write( "So line is \n" ); document.write( "\n" ); document.write( "So, tangecy point is at ( \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |