document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16570>Question 16570</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you Factor this equation?<BR>\n" );
document.write( "x squared+5x-14 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8095 by </B><A HREF=/tutors/aboutme.mpl?userid=kikerkins><B>kikerkins(17)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kikerkins><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x squared+5x-14\r<BR>\n" );
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document.write( "Ax(sqaured)+BX+C\r<BR>\n" );
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document.write( "To factor your equation we must find factors of -14, that add or subtract to be 5.  We have 1 and 14, No. 2 and 7, YES, 7-2 is 5.\r<BR>\n" );
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document.write( "(X+7)(X-2)\r<BR>\n" );
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document.write( "Because it is factors of -14, that means there is one positive and one negative factor( ie: +7,-2) and that makes sense because we need the 5 to stay positive, and 7-2 leaves us with a positive 5.\r<BR>\n" );
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document.write( "To check your work on any factoring problem, simply foil what you get [ (X+7)(X-2)], and it should equal the original quadratic(x squared+5x-14) if you did it correctly.\r<BR>\n" );
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