document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179950>Question 1179950</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2log x -log3 =log3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809499 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809499\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i get x = 3.\r<BR>\n" );
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document.write( "start with 2 * log(x) - log(3) = log(3)\r<BR>\n" );
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document.write( "add log(3) to both sides of the equation to get:\r<BR>\n" );
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document.write( "2 * log(x) = log(3) + log(3)\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "2 * log(x) = 2 * log(3)\r<BR>\n" );
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document.write( "divide both sides by 2 to get:\r<BR>\n" );
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document.write( "log(x) = log(3)\r<BR>\n" );
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document.write( "this is true if and only if x = 3.\r<BR>\n" );
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document.write( "you get:\r<BR>\n" );
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document.write( "2 * log(3) - log(3) = log(3)\r<BR>\n" );
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document.write( "another way to do it is:\r<BR>\n" );
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document.write( "start with 2 * log(x) - log(3) = log(3)\r<BR>\n" );
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document.write( "add log(3) to both sides to get:\r<BR>\n" );
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document.write( "2 * log(x) = log(3) + log(3)\r<BR>\n" );
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document.write( "since log(3) + log(3) = log(3 * 3) which is equal to log(3^2), this becomes:\r<BR>\n" );
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document.write( "2 * log(x) = log(3^2)\r<BR>\n" );
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document.write( "since 2 * log(x) = log(x^2), this becomes:\r<BR>\n" );
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document.write( "log(x^2) = log(3^2)\r<BR>\n" );
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document.write( "this is true if and only if x^2 = 3^2\r<BR>\n" );
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document.write( "simplify to get x^2 = 9\r<BR>\n" );
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document.write( "take the sqare root of both sides of this eqution to get:\r<BR>\n" );
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document.write( "x = plus or minus 3.\r<BR>\n" );
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document.write( "x can't be -3 because log of a negative number is not real, therefore x = 3.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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