document.write( "Question 1179842: Given the following date: 8,5,6,10,8,3,6 find the \r
\n" ); document.write( "\n" ); document.write( "A. Median\r
\n" ); document.write( "\n" ); document.write( "B.Sample Mean\r
\n" ); document.write( "\n" ); document.write( "C.Sample Standard Deviation\r
\n" ); document.write( "\n" ); document.write( "Explain your answers & show work.
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Algebra.Com's Answer #809439 by MathLover1(20855)\"\" \"About 
You can put this solution on YOUR website!
Given the following date: \"8\",\"5\",\"6\",\"10\",\"8\",\"3\",\"6\" find the\r
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\n" ); document.write( "\n" ); document.write( "A. Median\r
\n" ); document.write( "\n" ); document.write( "The median is the value separating the higher half of the data set, from the lower half.
\n" ); document.write( "If the number of terms is odd, then the median is the middle ellement of the sorted set.
\n" ); document.write( "If the number of terms is even, then the median is the arithmetic mean of the two middle elements of the sorted set.\r
\n" ); document.write( "\n" ); document.write( "sorted set:
\n" ); document.write( "\"3\",\"5\",\"6\",|\"highlight%286%29\"|,\"8\",\"8\",\"10\"\r
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\n" ); document.write( "\n" ); document.write( "Median=\"highlight%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "B.Sample Mean\r
\n" ); document.write( "\n" ); document.write( "mean(average) is the sum of the values in the set divided by the number of elements in that set\r
\n" ); document.write( "\n" ); document.write( "mean=\"%283%2B5%2B6%2B6%2B8%2B8%2B10%29%2F7=46%2F7=6.571428571\"\r
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\n" ); document.write( "\n" ); document.write( "C.Sample Standard Deviation\r
\n" ); document.write( "\n" ); document.write( "Standard Deviation is the square root of variance, so compute variance\r
\n" ); document.write( "\n" ); document.write( "Explanation
\n" ); document.write( "First, I added up all of the numbers:
\n" ); document.write( "\"3+%2B+5+%2B+6+%2B+6+%2B+8+%2B+8+%2B+10+=+46\"\r
\n" ); document.write( "\n" ); document.write( "I squared the total, and then divided the number of items in the data set
\n" ); document.write( "\"46%5E2%2F7+=+2116%2F7=+302.2857142857143\"\r
\n" ); document.write( "\n" ); document.write( "I took my set of original numbers from step 1, squared them individually this time, and added them all up:\r
\n" ); document.write( "\n" ); document.write( "\"3%5E2+%2B+5%5E2+%2B+6%5E2%2B+6%5E2%2B+8%5E2+%2B+8%5E2+%2B+10%5E2+=+334\"\r
\n" ); document.write( "\n" ); document.write( "I subtracted the amount in step 2 from the amount in step 3:\r
\n" ); document.write( "\n" ); document.write( "\"334+-+302.2857142857143+=+31.714285714285722\"\r
\n" ); document.write( "\n" ); document.write( "I subtracted 1 from the number of items in my data set:\"7+-+1+=+6\"\r
\n" ); document.write( "\n" ); document.write( "I divided the number in step 4 by the number in step 5:\r
\n" ); document.write( "\n" ); document.write( "\"31.714285714285722+%2F+6+=+5.28571428571\"=>This is my Variance!\r
\n" ); document.write( "\n" ); document.write( "Finally, I took the square root of the number from step 6 (the Variance),
\n" ); document.write( "\"sqrt%285.285714285714287%29+=+2.2990681\"=>This is my Standard Deviation!\r
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