document.write( "Question 1179832: If f(1)=3 and f(n)=āˆ’4f(nāˆ’1) then find the value of f(5). \n" ); document.write( "
Algebra.Com's Answer #809429 by MathLover1(20850)\"\" \"About 
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If \"f%281%29=3\" and \"f%28n%29=-4f%28n-1%29+\"then find the value of\"+f%285%29\"\r
\n" ); document.write( "\n" ); document.write( "This is a recursive formula which means it requires a previous output of the function to determine the next output. So find \"f%282%29\" based on the fact that you know what \"f%281%29+\"is. Then you can find \"f%283%29\", then \"f%284%29\", and finally\"+f%285%29\".\r
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\n" ); document.write( "\n" ); document.write( "if \"f%281%29=3+\", then
\n" ); document.write( "\"f%282%29=-4f%282-1%29\"
\n" ); document.write( "\"f%282%29=-4f%281%29\"
\n" ); document.write( "\"f%282%29=-4%2A3\"
\n" ); document.write( "\"f%282%29=-12\"\r
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\n" ); document.write( "\n" ); document.write( "if \"f%282%29=12\" , then
\n" ); document.write( "\"f%283%29=-4f%283-1%29\"
\n" ); document.write( "\"f%283%29=-4f%282%29\"
\n" ); document.write( "\"f%283%29=-4%28-12%29\"
\n" ); document.write( "\"f%283%29=48\"\r
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\n" ); document.write( "\n" ); document.write( "if \"f%283%29=48\" , then \r
\n" ); document.write( "\n" ); document.write( "\"f%284%29=-4f%284-1%29\"
\n" ); document.write( "\"f%284%29=-4f%283%29\"
\n" ); document.write( "\"f%284%29=-4%2A48\"
\n" ); document.write( "\"f%284%29=-192\"\r
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\n" ); document.write( "\n" ); document.write( "if \"f%284%29=-192\" , then \r
\n" ); document.write( "\n" ); document.write( "\"f%285%29=-4f%285-1%29\"
\n" ); document.write( "\"f%285%29=-4f%284%29\"
\n" ); document.write( "\"f%285%29=-4%28-192%29\"
\n" ); document.write( "\"f%285%29=768\"\r
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