document.write( "Question 1179771: A chemical company makes two brands of antifreeze. The first brand is 30% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 90 gallons of a mixture that contains 55% pure antifreeze, how many gallons of each brand of antifreeze must be used? \n" ); document.write( "

Algebra.Com's Answer #809345 by josgarithmetic(39618) $\"\"$ $\"About$

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Mixing 30% and 60% antifreezes
\n" ); document.write( "to make 90 gallons of 55% antifreeze\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "v gallons of the 60% antifreeze
\n" ); document.write( " $\"60v%2B30%2890-v%29=55%2A90\"$
\n" ); document.write( "-
\n" ); document.write( " $\"6v%2B3%2890-v%29=55%2A9\"$
\n" ); document.write( " $\"6v-3v%2B3%2A90=55%2A9\"$
\n" ); document.write( " $\"2v-v%2B90=55%2A3\"$
\n" ); document.write( " $\"v=55%2A3-90\"$
\n" ); document.write( " $\"highlight%28v=75%29\"$ ------gallons of the 60%
\n" ); document.write( "-
\n" ); document.write( " $\"highlight%2815%29\"$ ------gallons of the 30% \n" ); document.write( "

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