document.write( "Question 1179702: Regular octagon ABCDEFGH has a side length of
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Algebra.Com's Answer #809336 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let the side of square be \"a\"\r
\n" ); document.write( "\n" ); document.write( "the area \"A=a%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "since <\"+ABC\" (interior angle of the octagon) is \"135\"°, we can use cosine formula to calculate \"a\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=2%5E2%2B2%5E2-2%2A2%2A2%2Acos%28135%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=8-8%2Acos%28135%29\"....write \"cos%28135%29\" as a \"cos%28180-45%29=cos%28-45%29=-cos%2845%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=8-8%2A%28-cos%2845%29%29\"............\"-cos%2845%29=-sqrt%282%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=8-8%2A%28-sqrt%282%29%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=8%2B4sqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E2=13.7\"\r
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\n" ); document.write( "\n" ); document.write( "=> the area \"A=13.7cm%5E2\"\r
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