document.write( "Question 1179759: In Statistics and Probability examination, the average grade was 74 and the standard deviation was 7. If 11.9% of the class is given X’s scores, and the grades follow a normal distribution, what is the lowest possible score X and the highest possible score Y?
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Algebra.Com's Answer #809333 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi\r\n" );
document.write( "Normal Distribution: µ = 74 and σ = 7\r\n" );
document.write( "11.9% of the class is given X’s score\r\n" );
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document.write( " .0595 above and below the mean: .5 + .0595 = .5595\r\n" );
document.write( "invNorm(.5595,74,7) = 75\r\n" );
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document.write( "the highest possible score X is 75  (1 to the right of mean 74)\r\n" );
document.write( "lowest is 74 - 1 = 73\r\n" );
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document.write( "Your Reference did not work for me.\r\n" );
document.write( "If the intent was for 11.9% to get As...\r\n" );
document.write( "invNorm(.881,74,7) = 82.26  Round Up to next whole number\r\n" );
document.write( "or \r\n" );
document.write( "\"blue%28sigma%29%2Az+%2B+mu=blue+%28x%29\"   \"z%2A%28blue%28sigma%29%29+%2B+mu=blue+%28x%29\"\r\n" );
document.write( " 7*1.18 + 74 = 82.26  Round Up to next whole number\r\n" );
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document.write( "For As:  lowest is 83  and highest, would be a possible 100.\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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