document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110945>Question 110945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Miranda buys exactly 20 fish for $20.00. She pays $4.00/ea for Siamese fighting fish, $.50/ea for Betta fish, and $.25/ea for minnows. She bought at least one of each kind of fish. How many of each type of fish did she buy?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80933 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s+b+m=20 ... 4s+.5b+.25m=20 ... 3=s ... 1<=b<=16 ... 1<=m<=16\r<BR>\n" );
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document.write( "the cost of the Siamese helps to narrow the possibilities<BR>\n" );
document.write( "... if she buys less than 3 Siamese, then there is too much money remaining to keep the number of fish at 20<BR>\n" );
document.write( "... if she buys more than 3 Siamese, then there is not enough money to get the number AND variety of fish necessary\r<BR>\n" );
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document.write( "b+m=17 ... .5b+.25m=8 ... .5(17-m)+.25m=8 ... 8.5-.5m+.25m=8 ... -.25m=-.5 ... m=2 ... so b=15<BR>\n" );
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