document.write( "Question 1179758: there were 24 nickles, dimes, and quarters whose total value equaled $4.25. how many coins of each kind were there if the number of nickels equaled the number of dimes? \n" ); document.write( "

Algebra.Com's Answer #809325 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "Let x = # of nickels
\n" ); document.write( "Then x = # of dimes (same as the number of nickels)
\n" ); document.write( "And then 24-2x = # of quarters (the total number of coins is 24)

\n" ); document.write( "The total value of the coins is $4.25, or 425 cents:

\n" ); document.write( " $\"5%28x%29%2B10%28x%29%2B25%2824-2x%29=425\"$
\n" ); document.write( " $\"15x%2B600-50x=425\"$
\n" ); document.write( " $\"175=35x\"$
\n" ); document.write( " $\"x=5\"$

\n" ); document.write( "ANSWERS:
\n" ); document.write( "nickels: x = 5
\n" ); document.write( "dimes: x = 5
\n" ); document.write( "quarters: 24-2x=14

\n" ); document.write( "CHECK: 5(5)+10(5)+25(14)=25+50+350=425

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