document.write( "Question 1179739: The total price of 4 pens and 2 copies is rs 160 and that pen
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document.write( "Of 5 pen and 6 copies is rs 270 . Find the price of a single pen and single copy
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Algebra.Com's Answer #809313 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 4p + 2c = 160 (1)\r\n" ); document.write( "\r\n" ); document.write( " 5p + 6c = 270 (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Multiply equation (1) by 3 (both sides). Keep equation (2) as is.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 12p + 6c = 480 (1')\r\n" ); document.write( "\r\n" ); document.write( " 5p + 6c = 270 (2')\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From equation (1') subtract equation (1'). Doing this way, you eliminate the terms \"6c\", which cancel each other.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 12p - 5p = 480 - 270\r\n" ); document.write( "\r\n" ); document.write( " 7p = 210\r\n" ); document.write( "\r\n" ); document.write( " p = 210/7 = 30.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "To find \"c\", substitute the found value p= 30 into equation (1)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 4*30 + 2c = 160\r\n" ); document.write( "\r\n" ); document.write( " 120 + 2c = 160\r\n" ); document.write( "\r\n" ); document.write( " 2c = 160 - 120 = 40\r\n" ); document.write( "\r\n" ); document.write( " c = 40/2 = 20.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. A pen price is rs 30; a copy price is rs 20 for each.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The method I used in my solution is called \"the Elimination method\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You may check my solution on your own by substituting the found values into the original equations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |