document.write( "Question 1179655: The bird capable of the fastest flying speed is the swift. A swift flying with the wind to a favorite feeding spot traveled 42 mi in 0.3 h. On returning, now against the wind, the swift was able to travel only 27 mi in the same amount of time. What is the rate of the swift in calm air, and what was the rate of the wind? \n" ); document.write( "
Algebra.Com's Answer #809250 by mananth(16946)\"\" \"About 
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swift speed= x km/h
\n" ); document.write( " wind speed= y km/h
\n" ); document.write( " with wind speed= (x+y)
\n" ); document.write( " against wind speed (x-y)
\n" ); document.write( " d= 42 with wind
\n" ); document.write( " 42 / (x+y) = 0.3
\n" ); document.write( " divide by 0.3 0.3
\n" ); document.write( " 140 / (x+y) = 1
\n" ); document.write( " (x+y) = 140 ............1
\n" ); document.write( " d= = 27
\n" ); document.write( " 18/(x-y) = 0.3
\n" ); document.write( " divide by 0.3
\n" ); document.write( " 60 /(x-y) = 1
\n" ); document.write( " x - y = 60 .............2
\n" ); document.write( " add up (1) & (2)
\n" ); document.write( " 2 x = 200
\n" ); document.write( " / 2
\n" ); document.write( " x= 100 mph speed of swift without wind
\n" ); document.write( " plug value of x in (1)
\n" ); document.write( " we get y= 40 mph speed of wind
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