document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179649>Question 1179649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.51 and a standard deviation of 0.43. Using the empirical rule, what percentage of the students have grade point averages that are no more than 3.37? Please do not round your answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809235 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.37 = 2.51 + 2*.43<BR>\n" );
document.write( "3.37 is 2 SD Above or to the right of the mean<BR>\n" );
document.write( "percentage of the students have grade point averages that are no more than 3.37:<BR>\n" );
document.write( " .50 + 47.7 = 97.7\r<BR>\n" );
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document.write( "one  standard deviation from the mean accounts for about 68.2% of the set <BR>\n" );
document.write( "two standard deviations from the mean account for about 95.4% *******95.4/2 = 47.7<BR>\n" );
document.write( "and three standard deviations from the mean account for about 99.7%.<BR>\n" );
document.write( "Important to Understand z -values as they relate to the Standard Normal curve:<BR>\n" );
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