document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179662>Question 1179662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Divide 75 into two parts so that one part is 2/3 of the other. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #809222 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=809222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If one part is x<BR>\n" );
document.write( "the other part will be 2x/3\r<BR>\n" );
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document.write( "x+ 2x/3 =75\r<BR>\n" );
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document.write( "(3x+2x)/3=75\r<BR>\n" );
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document.write( "5x = 225<BR>\n" );
document.write( "x = 75\r<BR>\n" );
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document.write( "You can find the other part<BR>\n" );
document.write( "2/3 x\r<BR>\n" );
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document.write( " </SPAN>\n" );
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