document.write( "Question 1179625: A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot. y=-16x^2+228x+71
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Algebra.Com's Answer #809183 by MathLover1(20850)\"\" \"About 
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max height will be at vertex\r
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\n" ); document.write( "\n" ); document.write( " \"y=-16x%5E2%2B228x%2B71\"...rewrite in vertex form by completing square\r
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\n" ); document.write( "\n" ); document.write( " \"y=%28-16x%5E2%2B228x%29%2B71\"...factor out \"-16\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-16%28x%5E2-%2857%2F4%29x%2Bb%5E2%29-16b%5E2%2B71\".......\"b=%2857%2F4%29%2F2=%2857%2F8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-16%28x%5E2-%2857%2F4%29x%2B%2857%2F8%29%29-%28-16%2857%2F8%29%5E2%29%2B71\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-16%28x-57%2F8%29%5E2%2B3249%2F4%2B71\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-16%28x-57%2F8%29%5E2%2B3533%2F4\"=> \"h=57%2F8\" and \"k=3533%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "where \"k=3533%2F4\" is \"y\" coordinate of the vertex \r
\n" ); document.write( "\n" ); document.write( "so, max height is \"y=3533%2F4\" at \"x+=+57%2F8\"\r
\n" ); document.write( "\n" ); document.write( "to the nearest tenth of a foot: \"y=883.3\"\r
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