document.write( "Question 1179541:
\n" ); document.write( "The sum of three numbers is 87 . The second number is 2 times the third. The first number is 9 less than the third. What are the numbers?
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Algebra.Com's Answer #809089 by mananth(16946)\"\" \"About 
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The sum of three numbers is 87 .\r
\n" ); document.write( "\n" ); document.write( "let the numbers be x,y,z\r
\n" ); document.write( "\n" ); document.write( "x+y+z=87 ---------------------------(1)\r
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\n" ); document.write( "\n" ); document.write( " The second number is 2 times the third.
\n" ); document.write( "y=2z\r
\n" ); document.write( "\n" ); document.write( " The first number is 9 less than the third.\r
\n" ); document.write( "\n" ); document.write( "x = z-9\r
\n" ); document.write( "\n" ); document.write( "substitute y & z in (1)
\n" ); document.write( "z-9 +2z +z =87\r
\n" ); document.write( "\n" ); document.write( "4z-9 = 87
\n" ); document.write( "4z = 96
\n" ); document.write( "z= 24\r
\n" ); document.write( "\n" ); document.write( "knowing z you can find x & y\r
\n" ); document.write( "\n" ); document.write( " the numbers
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