document.write( "Question 1179336: Find h'(3) if h (x)=7x + 4/(x^2-1)^(1/3) . \n" ); document.write( "

Algebra.Com's Answer #808871 by Boreal(15235) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm assuming h(x)=7x + 4/(x^2-1)^(1/3), two terms.
\n" ); document.write( "derivative= 7+4/(x^2-1)^(1/3)=4(x^2-1)^(-1/3)
\n" ); document.write( "=7 (-1/3)*4(x^2-1)^(*-4/3)*2x
\n" ); document.write( "when x=3,
\n" ); document.write( "=7-(8/3)x*(8)^(-4/3), but 8^(-4/3) is 1/8*(4/3) or 1/16; so -(8/3)*3*(1/16)=-1/2
\n" ); document.write( "=6.5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );