document.write( "Question 1179343: The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 32 liters, and standard deviation of 9.5 liters.\r
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\n" ); document.write( "\n" ); document.write( "B) What is the probability that daily production is more than 58.6 liters? (Round your answer to 4 decimal places.) \n" ); document.write( "
Algebra.Com's Answer #808865 by ewatrrr(24785)\"\" \"About 
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document.write( "Hi\r\n" );
document.write( "Distribution: normal with µ = 32 and σ = 9.5\r\n" );
document.write( "probability that daily production is:\r\n" );
document.write( "Continuous Curve:\r\n" );
document.write( "Using TI or similarly an inexpensive calculator like an Casio fx-115 ES plus\r\n" );
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document.write( "P( x < 35.9) = P( x ≤ 35.9) =  normalcdf(-9999, 35.9,32,9.5) = .6593\r\n" );
document.write( "Or\r\n" );
document.write( "P( x >  58.6) = 1 - P( x ≤ 58.6) = 1 - normalcdf(-9999, 58.6,32,9.5) = 1-.9974 = .0026\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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