document.write( "Question 1179308: a number of dimes and quarters have a total value of 1975. if there are 5 fewer quarters than twice the number of dimes find the number of dimes. please use substitution or elimination to solve \n" ); document.write( "
Algebra.Com's Answer #808835 by josgarithmetic(39628)\"\" \"About 
You can put this solution on YOUR website!
What total value? Dollars or in cents?\r
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\n" ); document.write( "\n" ); document.write( "d dimes
\n" ); document.write( "q quarters
\n" ); document.write( "\"2d-q=5\"
\n" ); document.write( "\"q=2d-5\"\r
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\n" ); document.write( "\n" ); document.write( "Assuming you are given 1975 CENTS, then \"10d%2B25%282d-5%29=1975\", and you can do the rest.\r
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\n" ); document.write( "\n" ); document.write( "If the missing money unit is \"dollar\", and that value is really $1975, then this means 197500 cents. You know what to do.
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\n" ); document.write( "\"10d%2B25%282d-5%29=197500\"\r
\n" ); document.write( "\n" ); document.write( "\"2d%2B5%282d-5%29=39500\"\r
\n" ); document.write( "\n" ); document.write( "\"12d-25=39500\"\r
\n" ); document.write( "\n" ); document.write( "\"12d=39525\"\r
\n" ); document.write( "\n" ); document.write( "\"d=3293.75\"---------the description of the problem(probably) is wrong.\r
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\n" ); document.write( "\n" ); document.write( "\"10d%2B25%282d-5%29=1975\" if it WERE actually cents\r
\n" ); document.write( "\n" ); document.write( "\"2d%2B5%282d-5%29=395\"\r
\n" ); document.write( "\n" ); document.write( "\"12d-25=395\"\r
\n" ); document.write( "\n" ); document.write( "\"12d=420\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28d=35%29\"---------the number of DIMES
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