document.write( "Question 1179275: Calculate the total number of different permutations of all letters A, B, C, D, E, F when
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document.write( "a) there are no restrictions,
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document.write( "b) the letters A and B are to be adjacent to one another,
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document.write( "c) the first letter is A, B or C and the last letter is D, E or F.
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Algebra.Com's Answer #808826 by ikleyn(52873) You can put this solution on YOUR website! . \n" ); document.write( "Calculate the total number of different permutations of all letters A, B, C, D, E, F when \n" ); document.write( "a) there are no restrictions, \n" ); document.write( "b) the letters A and B are to be adjacent to one another, \n" ); document.write( "c) the first letter is A, B or C and the last letter is D, E or F. \n" ); document.write( "~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(a) 6! = 6*5*4*3*2*1 = 720.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(b) You concider the pair of letters AB as one glued object;\r\n" ); document.write( "\r\n" ); document.write( " so you have 5 object to permutate, in all, which produces 5! = 5*4*3*2*1 = 120 different permutations.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Another 120 different permutations you have with the object BA instead of AB.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " So, in total, there are 120 + 120 = 240 such permutations.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(c) You have 3 possibility for the first letter (A, B or C).\r\n" ); document.write( "\r\n" ); document.write( " Similarly, you have 3 possibility for the last letter (D, E or F).\r\n" ); document.write( "\r\n" ); document.write( " Finally, you have 4! = 4*3*2*1 = 24 permutations for the remaining 6-2 = 4 letters.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " Hence, in all, there are 3*3*24 = 216 possible permutations, satisfying the imposed conditions.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "----------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On Permutations, see introductory lessons \r \n" ); document.write( "\n" ); document.write( " - Introduction to Permutations\r \n" ); document.write( "\n" ); document.write( " - PROOF of the formula on the number of Permutations\r \n" ); document.write( "\n" ); document.write( " - Simple and simplest problems on permutations\r \n" ); document.write( "\n" ); document.write( " - Special type permutations problems \r \n" ); document.write( "\n" ); document.write( " - Problems on Permutations with restrictions \r \n" ); document.write( "\n" ); document.write( " - OVERVIEW of lessons on Permutations and Combinations\r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-II in this site\r \n" ); document.write( "\n" ); document.write( " - ALGEBRA-II - YOUR ONLINE TEXTBOOK.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Combinatorics: Combinations and permutations\". \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Save the link to this textbook together with its description\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-II \n" ); document.write( "https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "into your archive and use when it is needed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |