document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179298>Question 1179298</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of the following:\r<BR>\n" );
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document.write( "1.(3t)°<BR>\n" );
document.write( "2. 66⁰+10°<BR>\n" );
document.write( "3.7x°-(6x)°<BR>\n" );
document.write( "4. 100°+100°<BR>\n" );
document.write( "5. 4+t°<BR>\n" );
document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #808817 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=808817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "Anything raised to the power 0 is 1\r<BR>\n" );
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document.write( "(3t)° =1\r<BR>\n" );
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document.write( "2. 66⁰+10°\r<BR>\n" );
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document.write( "1+1 =2<BR>\n" );
document.write( "3.7x°-(6x)°<BR>\n" );
document.write( "7*1-1=6\r<BR>\n" );
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document.write( "4. 100°+100°\r<BR>\n" );
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document.write( "1+1=2\r<BR>\n" );
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document.write( "5. 4+t°\r<BR>\n" );
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document.write( "4+1=5 </SPAN>\n" );
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