document.write( "Question 1179276: The top and bottom diameters of a bucket are 20cm and 16cm respectively. If the bucket is 40cm deep, calculate its surface area. \n" ); document.write( "
Algebra.Com's Answer #808814 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Total surface area of a conical frustum:
\n" ); document.write( "A = π * [ r1^2 + r2^2 + (r1 + r2) * √((r1 - r2)2 + h^2) ]\r
\n" ); document.write( "\n" ); document.write( "r1=20 cm
\n" ); document.write( "r2=16 cm
\n" ); document.write( "h= 40 cm
\n" ); document.write( "pi = 3.142\r
\n" ); document.write( "\n" ); document.write( "A=3.14*(20^2+16^2+ (20+16)*sqrt(20-16)^2+40^2\r
\n" ); document.write( "\n" ); document.write( "A= 3.142*(656 +36*sqrt(16 +40^2)
\n" ); document.write( "=6608 cm^2
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