document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52500>Question 52500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Junior's boat will go 15 miles per hour in still water.  If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80881 by </B><A HREF=/tutors/aboutme.mpl?userid=mathdude2><B>mathdude2(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathdude2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "The above solution is not correct.<BR>\n" );
document.write( "Here is the correct solution:\r<BR>\n" );
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document.write( "Using the formula t=s/v \r<BR>\n" );
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document.write( "where t=time, s=distance, v=speed \r<BR>\n" );
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document.write( "      12/(15+x)=9/(15-x) \r<BR>\n" );
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document.write( "Solving for X, multiply both sides by (15-x)/(15+x) \r<BR>\n" );
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document.write( "      12(15-x)=9(15+x) \r<BR>\n" );
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document.write( "      180-12x=135+9x \r<BR>\n" );
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document.write( "      180-135=12x+9x \r<BR>\n" );
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document.write( "       45=21x \r<BR>\n" );
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document.write( "       x=45/21=15/7 = 2 1/7\r<BR>\n" );
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document.write( "Then the speed of the current x=15/7 or 2 1/7 miles per hour.<BR>\n" );
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