document.write( "Question 1179267: Find y in terms of x when 2logarithm of y to base 3 - 4 = 3logarithm of (x+2) to base 3 \n" ); document.write( "
Algebra.Com's Answer #808785 by greenestamps(13215)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "\"2log%283%2Cy%29+=+log%283%2Cy%5E2%29\"

\n" ); document.write( "\"3log%283%2Cx%2B2%29+=+log%283%2C%28x%2B2%29%5E3%29\"

\n" ); document.write( "So the equation is

\n" ); document.write( "\"log%283%2Cy%5E2%29-4=log%283%2C%28x%2B2%29%5E3%29\"

\n" ); document.write( "Write the \"4\" as \"log%283%2C3%5E4%29\"

\n" ); document.write( "Then

\n" ); document.write( "\"log%283%2Cy%5E2%29-log%283%2C3%5E4%29=log%283%2C%28x%2B2%29%5E3%29\"

\n" ); document.write( "Now use rules of logarithms to write the expression on the left as a single logarithm. The equation is now of the form \"log%283%2CA%29=log%283%2CB%29\", which means A=B.

\n" ); document.write( "You should be able to finish from there.

\n" ); document.write( "
\n" ); document.write( "
\n" );