document.write( "Question 1179258: On
\n" ); document.write( " the first day, Cindy sells 6 adult tickets and 5 children's tickets for a total of 112.50. on the second day, she sells 8 adult tickets and 4 children's tickets for a total of 130.00
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Algebra.Com's Answer #808781 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "The first tutor always solves systems of equations using substitution. That might be her preferred method; but when both equations are given in Ax+By=C form, I think some sort of elimination is much easier.

\n" ); document.write( "Below is an unusual method for solving the problem. I first present the solution informally using logical reasoning; then I show the corresponding formal algebraic solution. The method shown can make the solution of some similar problems easier than standard elimination; but for most problems a more straightforward solution using elimination will be fastest.

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\n" ); document.write( "\"On the first day, Cindy sells 6 adult tickets and 5 children's tickets for a total of 112.50.\"
\n" ); document.write( "\"On the second day, she sells 8 adult tickets and 4 children's tickets for a total of 130.00\"

\n" ); document.write( "The difference between the two sales is 2 more adult tickets and 1 fewer children's tickets for $17.50 more.

\n" ); document.write( "Apply that difference four more times to make the number of children's tickets zero. Doing that gives us 8+4(2) = 16 adult tickets and 4-4(1) = 0 children's tickets for a total of $130+4($17.50)=$200.

\n" ); document.write( "So the cost of each adult ticket is $200/16 = $12.50.

\n" ); document.write( "Then use the purchase on the second day to determine the cost of each children's ticket:
\n" ); document.write( "8($12.50)+4x = $130
\n" ); document.write( "4x = $30
\n" ); document.write( "x = $30/4 = $7.50

\n" ); document.write( "ANSWER: Adult ticket price $12.50; Children's ticket price $7.50

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\n" ); document.write( "Algebraically, this unusual solution method looks like this:

\n" ); document.write( "\"system%286a%2B5c=112.5%2C8a%2B4c=130%29\"

\n" ); document.write( "Find the difference between the two equations:

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\n" ); document.write( "Multiply the second equation by 4:

\n" ); document.write( "\"system%288a%2B4c=130%2C8a-4c=70%29\"

\n" ); document.write( "Add the two equations to eliminate c:

\n" ); document.write( "\"16a=200\"
\n" ); document.write( "\"a+=+200%2F16+=+12.50\"

\n" ); document.write( "Use that value for a to find c:

\n" ); document.write( "\"8%2812.50%29%2B4c+=+130\"
\n" ); document.write( "\"4c+=+30\"
\n" ); document.write( "\"c+=+7.50\"

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\n" ); document.write( "So why use this unusual method for solving the problem?

\n" ); document.write( "In a formal algebraic solution, finding the difference between the two original equations gives us an equation in which one of the coefficients is -1. That will make solving the system by elimination easier, because it will keep the coefficients smaller.

\n" ); document.write( "And if a formal algebraic solution is not required, this method of solving the problem makes an informal solution easier, for the same reason.

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