document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1179231>Question 1179231</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the measure of the obtuse angle formed by the hands of a clock at 10:25? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #808761 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=808761\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "One way to solve this kind of problem -- the way I find \"works\" for me -- is to determine the \"clockwise\" angle each hand of the clock makes with 12:00.<br><BR>\n" );
document.write( "The hour hand moves at 30 degrees per hour (360 degrees in 12 hours), or 0.5 degrees per minute.  For your problem, determine how many degrees past 12:00 the hour hand has moved at 10:25 (10 hours at 30 degrees per hour, plus 25 minutes at 0.5 degrees per hour).<br><BR>\n" );
document.write( "The minute hand moves 6 degrees per minute (360 degrees in 60 minutes).  For your problem, determine how many degrees past 12:00 the minute hand has moved at 10:25.<br><BR>\n" );
document.write( "Find the difference between those two angles.  The problem asks for the obtuse angle (between 90 and 180 degrees); if that difference is greater than 180 degrees, then the number you want is 360 degrees minus that difference.<br><BR>\n" );
document.write( "You can have the pleasure of doing the calculations and finding the answer by yourself.<br><BR>\n" );
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