document.write( "Question 110869: One day, the temperature at 11:00 A.M. was 44°F, and by 4:00 P.M. the temperature was 54°F. What was the hourly rate of temperature change?\r
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Algebra.Com's Answer #80876 by bucky(2189)\"\" \"About 
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There are five hours between 11:00 a.m. and 4:00 p.m.
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\n" ); document.write( "During that time the temperature went from 44°F to 54°F, a change of +10°F.
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\n" ); document.write( "The average hourly rate of change is the change in temperature divided by the change in time:
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\n" ); document.write( "Rate = 10°F/5 hr = +2°F/hr
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\n" ); document.write( "The rate of change is read as +2°F per hour with the + sign indicating that the temperature
\n" ); document.write( "was increasing each hour.
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\n" ); document.write( "Note this is the \"average\" rate for the entire period of 5 hours. In \"real life\" the temperature
\n" ); document.write( "might not have changed during the first couple of hours and then it could have increased
\n" ); document.write( "at a faster rate during the last hour or two ... just enough to make the total change 10°F
\n" ); document.write( "by the end of the 5 hours.
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\n" ); document.write( "Hope this helps you to understand the problem.
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