document.write( "Question 1179222: At a local Brownsville play production, 420 tickets were sold. The ticket prices varied on the seating arrangements and cost $8, $10, or $12. The total income from ticket sales reached $3920. If the combined number of $8 and $10 priced tickets sold was 5 times the number of $12 tickets sold, how many tickets of each type were sold? \n" ); document.write( "
Algebra.Com's Answer #808745 by josgarithmetic(39623)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "PRICES COUNTS COSTS\r\n" ); document.write( " 8 e 8e\r\n" ); document.write( " 10 420-e-t 10(420-e-t)\r\n" ); document.write( " 12 t 12t\r\n" ); document.write( " 420 3920\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "First equation gives \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Second equation simplifies to \n" ); document.write( "Substitution gives \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Quantity of $10 tickets by difference, |