document.write( "Question 1179222: At a local Brownsville play production, 420 tickets were sold. The ticket prices varied on the seating arrangements and cost $8, $10, or $12. The total income from ticket sales reached $3920. If the combined number of $8 and $10 priced tickets sold was 5 times the number of $12 tickets sold, how many tickets of each type were sold? \n" ); document.write( "
Algebra.Com's Answer #808745 by josgarithmetic(39623)\"\" \"About 
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document.write( "PRICES         COUNTS           COSTS\r\n" );
document.write( "  8              e               8e\r\n" );
document.write( " 10            420-e-t          10(420-e-t)\r\n" );
document.write( " 12              t              12t\r\n" );
document.write( "               420               3920\r\n" );
document.write( "

\n" ); document.write( "\"system%28e%2B420-e-t=5t%2C8e%2B10%28420-e-t%29%2B12t=3920%29\"\r
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\n" ); document.write( "\n" ); document.write( "First equation gives \"highlight%28t=70%29\".\r
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\n" ); document.write( "\n" ); document.write( "Second equation simplifies to \"e-t=140\".
\n" ); document.write( "Substitution gives \"highlight%28e=210%29\".\r
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\n" ); document.write( "\n" ); document.write( "Quantity of $10 tickets by difference, \"highlight%28140%29\".
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