document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16558>Question 16558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 14+3x(x+2)=-7x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8087 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8087\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 14+3x(x+2)=-7x<BR>\n" );
document.write( "14+3x^2+6x+7x=0<BR>\n" );
document.write( "3x^2+13x+14=0<BR>\n" );
document.write( "  now find 2 factors for the product of coefficient of x^2 (3) and constant term (14) which will add up to the coefficient of x (13)<BR>\n" );
document.write( "   the 2 factors of 3*14=42 which add up to 13 are 6 and 7.hence<BR>\n" );
document.write( "  3x^2+6x+7x+14=0<BR>\n" );
document.write( "  3x(x+2)+7(x+2)=0..NOTE THAT THIS COULD BE WRITTEN DIRECTLY FROM FIRST TWO STEPS NAMELY 14+3x(x+2)=-7x<BR>\n" );
document.write( "              14+3x^2+6x+7x=0<BR>\n" );
document.write( "  but i showed you the working to do any other problem.<BR>\n" );
document.write( "  so (x+2)(3x+7)=0<BR>\n" );
document.write( "       x+2=0   OR   3x+7=0<BR>\n" );
document.write( "        x=-2     OR  3x=-7..x=-7/3\r<BR>\n" );
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document.write( " </SPAN>\n" );
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