document.write( "Question 1179135: Prove 4•10^(2n)+9•10^(2n-1)+5 is divisible by 99 for n is in N. \n" ); document.write( "
Algebra.Com's Answer #808654 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "Assuming that \r
\n" ); document.write( "\n" ); document.write( "\"4%2A10%5E%282n%29%2B9%2A10%5E%282n-1%29%2B5=99k\"\r
\n" ); document.write( "\n" ); document.write( "\"4%2A10%5E%282n%2B1%29%2B9%2A10%5E%282n%2B1%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "=\"100%2A4%2A10%5E%282n%29%2B100%2A9%2A10%5E%282n-1%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "=\"100%2A4%2A10%5E%282n%29%2B9%2A10%5E%282n-1%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "=\"100%2A%284%2A10%5E%282n%29%2B9%2A10%5E%282n-1%2B5-5%29%29%2B5\"\r
\n" ); document.write( "\n" ); document.write( "=\"100%2A%284%2A10%5E%282n%29%2B9%2A10%5E%282n-1%2B5%29%29-500%2B5\"\r
\n" ); document.write( "\n" ); document.write( "=\"100%2A99k-495\"\r
\n" ); document.write( "\n" ); document.write( "=\"100%2A99k-5%2A99\"\r
\n" ); document.write( "\n" ); document.write( "=\"%28100k-5%29%2A99\" => \"99\" is a factor, means it is divisible by \"99+\"\r
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