document.write( "Question 110861: 1. If x + a/x = b then find the value of (x^2 + bx + a)/(bx^2 - x^3) \r
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document.write( "2. If x + 1/x = 99, find the value of 100x/(3x^2 + 103x + 3)\r
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document.write( "Question from Tata Mc Graw-Hill NTSE book \n" );
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Algebra.Com's Answer #80865 by edjones(8007)![]() ![]() You can put this solution on YOUR website! x + a/x = b \n" ); document.write( "(x^2 + bx + a)/(bx^2 - x^3) \n" ); document.write( "(x^2+x(x + a/x)+a/(x^2(x + a/x )-x^3 \n" ); document.write( "(x^2+x^2 + a +a)/(x^3 + ax -x^3) \n" ); document.write( "(2x^2+2a)/ax \n" ); document.write( ". \n" ); document.write( "x + 1/x = 99 \n" ); document.write( "x^2+1=99x eliminate fractions multiply each side by x \n" ); document.write( "x^2-99x+1=0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "I'll let you plug the answers for x into the equation below to get the answers which should both be .25 \n" ); document.write( "100x/(3x^2 + 103x + 3) \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |