document.write( "Question 1179143: What is the inequalities of -2x > 0? \n" ); document.write( "

Algebra.Com's Answer #808631 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( " $\"-2x+%3E+0\"$ ........divide by $\"-2\"$ , don't forget to change a sign\r
\n" ); document.write( "\n" ); document.write( " $\"-2x%2F-2+%3E+0%2F-2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x+%3C+0\"$ \r
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\n" ); document.write( "\n" ); document.write( "interval solution:\r
\n" ); document.write( "\n" ); document.write( "( $\"-infinity\"$ , $\"0\"$ )\r
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\n" ); document.write( "\n" ); document.write( "so, $\"-2x+%3E+0\"$ will be true for all negative real numbers\r
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\n" ); document.write( "\n" ); document.write( " $\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-2x+%3E+0%29+\"$ \r
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