document.write( "Question 1179118: A number exceed another by 5, the sum of their square is 157. What are the numbers? \n" ); document.write( "
Algebra.Com's Answer #808624 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x = one of the numbers and y = the other. \n" ); document.write( "if x exceeds y by 5, then x = y + 5 \n" ); document.write( "the sum of their squares is 157. \n" ); document.write( "this means x^2 + y^2 = 157 \n" ); document.write( "since x = y + 5, then replace x with y + 5 in that equation to get: \n" ); document.write( "(y + 5)^2 + y^2 = 157 \n" ); document.write( "simplify to get: \n" ); document.write( "y^2 + 10y + 25 + y^2 = 157 \n" ); document.write( "combine like terms to get: \n" ); document.write( "2y^2 + 10y + 25 = 157 \n" ); document.write( "subtract 157 from both sides of the equation to get: \n" ); document.write( "2y^2 + 10y - 132 = 0 \n" ); document.write( "divide both sides of this equation by 2 to get: \n" ); document.write( "y^2 + 5y - 66 = 0 \n" ); document.write( "factor this quadratic equation to get: \n" ); document.write( "(y + 11) * (y - 6) = 0 \n" ); document.write( "solve for y to get: \n" ); document.write( "y = -11 or y = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when y = 6, x = y + 5 = 11 \n" ); document.write( "when y = -11, x = y + 5 = -6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when y = 6 and x = 11, then 6^2 + 11^2 = 36 + 121 = 157 \n" ); document.write( "when y = -11 and x = -6, then (-11)^2 + (-6)^2 = 121 + 36 = 157.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your numbers can be: \n" ); document.write( "(6 and 11) or (-11 and -6).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |