document.write( "Question 1179095: A 99% confidence interval (in inches) for the mean height of a population is 65.7 < μ < 67.3. This
\n" ); document.write( "result is based on a sample of size 144. Construct the 95% confidence interval. (Hint: you will first
\n" ); document.write( "need to find the sample mean and sample standard deviation).\r
\n" ); document.write( "\n" ); document.write( "I'm struggling to find the mean and the standard deviation of this question. \n" ); document.write( "

Algebra.Com's Answer #808600 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "Hi\r\n" );
document.write( "x̄ - ME <  < x̄ + ME\r\n" );
document.write( "A 99% confidence interval...\r\n" );
document.write( "65.7 < μ < 67.3   | ME = (67.3-65.7)/2 = 1.6/2 = .8\r\n" );
document.write( "x̄ = 66.5\r\n" );
document.write( "ME =\r\n" );
document.write( " .8 = \r\n" );
document.write( " (.8)(12) /2.576 = σ = 3.727\r\n" );
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document.write( "Construct the 95% confidence interval. \r\n" );
document.write( "ME = = 1.96*(3.727)/12 = .6 (rounded to nearest tenth)\r\n" );
document.write( "x̄ - ME <  < x̄ + ME\r\n" );
document.write( "66.5 - .6 <  < 66.5 +.6\r\n" );
document.write( "  65.9  <  < 67.1\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( " = CI	z = value\r\n" );
document.write( "90%	z =1.645\r\n" );
document.write( "92%	z = 1.751\r\n" );
document.write( "95%	z = 1.96\r\n" );
document.write( "98%	z = 2.326\r\n" );
document.write( "99%	z = 2.576\r\n" );
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