document.write( "Question 1179073: Find the inverse of the one-to-one function.
\n" ); document.write( "f(x)=3x+1/4
\n" ); document.write( "

Algebra.Com's Answer #808576 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The method shown by the other tutor is fine: switch the x and y in the given function and solve for the new y. That method is often needed for complicated functions.

\n" ); document.write( "For relatively simple functions like this, there is a much easier way to find the inverse, using the idea that the inverse function \"gets you back where you started\" by \"un-doing\" what the function does.

\n" ); document.write( "What does the given function do to the input?
\n" ); document.write( "(1) multiply by 3; and
\n" ); document.write( "(2) add 1/4

\n" ); document.write( "The inverse function has to undo those operations, using the inverse operations in the opposite order.

\n" ); document.write( "Inverse function:
\n" ); document.write( "(1) subtract 1/4; and
\n" ); document.write( "(2) divide by 3

\n" ); document.write( "ANSWER: The inverse function is
\n" ); document.write( "\"f%28x%29=%28x-1%2F4%29%2F3\"

\n" ); document.write( "Change the format if desired or required....

\n" ); document.write( "-------------------------------------------------------------------------------------

\n" ); document.write( "The words of explanation make this look like a long process. But here is all that is really involved:

\n" ); document.write( "given function: multiply by 3; add 1/4
\n" ); document.write( "inverse function: subtract 1/4; divide by 3

\n" ); document.write( "
\n" ); document.write( "
\n" );